National League for Nursing (NLN) Science Practice Exam

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A 60-watt light bulb is powered by a 110-volt power source. What is the current being drawn?

1.83 amperes
0.55 amperes
50 amperes
6,600 amperes

The correct answer is: 0.55 amperes

To determine the current drawn by a 60-watt light bulb powered by a 110-volt source, we can use the formula derived from Ohm's Law and the power equation: Power (P) = Voltage (V) × Current (I) Rearranging this formula to find current gives: Current (I) = Power (P) / Voltage (V) Substituting the values: I = 60 watts / 110 volts = 0.545 amperes When rounded, this shows that the current drawn is approximately 0.55 amperes. This calculation accurately reflects how electrical power works: the wattage of the bulb indicates how much power it consumes, and by dividing that by the voltage of the power source, we can find the amount of current flowing through the circuit. Therefore, this reasoning confirms that the correct answer is the option that indicates 0.55 amperes.